Summary of "Molarity, Molality, Volume & Mass Percent, Mole Fraction & Density - Solution Concentration Problems"

Summary of Video:

"Molarity, Molality, Volume & Mass Percent, Mole Fraction & Density - Solution Concentration Problems"


Main Concepts and Definitions:

  1. Solution Components:
    • Solute: Substance being dissolved (e.g., Sodium Chloride).
    • Solvent: Substance doing the dissolving (e.g., water).
    • Solution: Solute + Solvent combined.
  2. Concentration Units and Formulas:
    • Mass Percent (%) Mass % = (mass of solute / mass of solution) × 100
    • Volume Percent (v/v %) Volume % = (volume of solute / volume of solution) × 100
    • Mole Fraction (X): For substance A in a mixture: XA = moles of A / total moles in solution
    • Molarity (M): M = moles of solute / liters of solution Volume must be in liters.
    • Molality (m): m = moles of solute / kilograms of solvent Note: Molality uses mass of solvent, not solution.
    • Density (ρ): ρ = mass / volume Common units: g/mL or g/cm³ (1 mL = 1 cm³). Useful conversions:
      • 1 L = 1000 mL
      • 1 kg = 1000 g

Important Distinctions:


Step-by-Step Problem-Solving Methodology:

  1. Identify solute and solvent.
  2. Use the correct formula based on the concentration unit asked.
  3. Convert units as necessary:
    • Grams to moles (using molar mass).
    • Milliliters to liters (for Molarity).
    • Grams to kilograms (for Molality).
  4. Calculate total mass or volume of solution if not given (solute + solvent).
  5. Use Density to convert between mass and volume if needed.
  6. Plug values into formulas and solve.

Example Problems and Solutions:

  1. Mass Percent of NaCl: Given 15 g NaCl + 225 g water → total solution = 240 g. Mass % NaCl = (15/240) × 100 = 6.25%.
  2. Volume Percent of Methanol and Mass Percent of Water: Methanol volume = 25 mL, Water volume = 150 mL → solution volume = 175 mL. Volume % Methanol = (25/175) × 100 = 14%. Use Density to find mass:   - Methanol mass = 25 mL × 0.792 g/mL = 19.8 g   - Water mass = 150 mL × 1 g/mL = 150 g Total mass = 169.8 g Mass % water = (150/169.8) × 100 = 88.3%.
  3. Mole Fraction of KCl: 2 moles KCl + 8 moles water → total moles = 10. Mole Fraction KCl = 2/10 = 0.2.
  4. Mole Fraction of NaF: Convert 25 g NaF to moles:   - Molar mass NaF ≈ 42 g/mol → 25/42 = 0.595 moles. Convert 200 g water to moles:   - Molar mass H₂O ≈ 18 g/mol → 200/18 = 11.1 moles. Mole Fraction NaF = 0.595 / (0.595 + 11.1) ≈ 0.

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