Summary of "CHEMICAL EQUILIBRIUM in 1 Shot || All Concepts & PYQs Covered || Prachand NEET"
Core ideas and definitions
Chemical equilibrium (dynamic equilibrium): a stage in a reversible reaction (usually in a closed system) where measurable macroscopic properties (concentration, pressure, etc.) stop changing with time even though forward and backward reactions continue. Net rate of reaction = 0 because rate(forward) = rate(backward).
- “Saturation” is an informal term sometimes used to describe reaching equilibrium; do not confuse this with reactions stopping — at equilibrium reactions continue microscopically (dynamic).
- Reaction quotient Q vs equilibrium constant K:
- Q < K → reaction shifts forward (more product formed).
- Q = K → system at equilibrium.
- Q > K → reaction shifts backward (more reactant formed).
- Size of K:
- K >> 1 (e.g., > 10^3) → products favored at equilibrium.
- K << 1 → reactants favored.
- K ~ 1 → significant amounts of both reactants and products.
Types / classifications of equilibrium
- By change type:
- Physical equilibrium: phase changes (solid ↔ liquid, liquid ↔ vapor, sublimation, solubility equilibria). No chemical change at molecular level.
- Chemical equilibrium: chemical conversion (A ⇌ B); includes ionic equilibria (acid–base, dissociation).
- By phases present:
- Homogeneous equilibrium: reactants and products all in the same phase (e.g., all gases).
- Heterogeneous equilibrium: more than one phase (e.g., CaCO3(s) ⇌ CaO(s) + CO2(g)).
Active mass / activities (practical rules)
- For gases: active mass ≈ partial pressure (use pressure in Kp expressions).
- For solutions: active mass ≈ concentration (use molarity in Kc expressions).
- For pure solids and pure liquids: activity ≈ 1 (omit these from equilibrium expressions).
- Practical exam convention: if volume is not given in mole problems, you can assume 1 L so moles ≈ molarity to simplify numerics.
Law of Mass Action and equilibrium-constant expressions
- Rate laws (mass action): rate ∝ product of active masses of reactants raised to their stoichiometric coefficients.
- For a general reaction aA + bB ⇌ cC + dD:
- Kc = [C]^c [D]^d / ([A]^a [B]^b) (concentrations)
- Kp = (PC)^c (PD)^d / (PA)^a (PB)^b (partial pressures)
- Kx or K (mole-fraction based) can be written using mole fractions.
- Relating Kp and Kc:
- Kp = Kc (RT)^{Δn}, where Δn = (moles gas products) − (moles gas reactants). Use R in consistent units and T in K.
- Units of Kp or Kc depend on Δn—derive units carefully when requested.
- Thermodynamic relation:
- ΔG° = −RT ln K (connects standard free energy and equilibrium constant).
- van ’t Hoff (temperature dependence): ln(K2/K1) = −ΔH°/R (1/T2 − 1/T1) (assumes ΔH° constant).
- If ΔH° > 0 (endothermic): K increases with temperature.
- If ΔH° < 0 (exothermic): K decreases with temperature.
- Manipulating equilibrium constants:
- Reverse a reaction → new K = 1 / K(original).
- Multiply reaction by n → new K = [K(original)]^n.
- Add reactions → overall K = product of individual Ks.
Le Chatelier’s principle (qualitative predictor of shifts)
If a stress is applied to a system at equilibrium, the system shifts to partially oppose the stress and establish a new equilibrium.
Common stresses and effects:
- Concentration changes:
- Increasing concentration of a reactant → equilibrium shifts to consume that reactant (toward products).
- Increasing concentration of a product → shifts toward reactants.
- Temperature changes:
- Treat temperature as “heat”: for a forward endothermic reaction (heat on reactant side), increasing T favors the forward direction; for exothermic forward reaction, increasing T favors reverse.
- Temperature changes alter K (not just the position); increasing T favors the side that absorbs heat.
- Pressure/volume changes (gaseous systems only):
- Increasing pressure (decreasing volume) shifts toward the side with fewer moles of gas.
- Decreasing pressure (increasing volume) shifts toward the side with more moles of gas.
- If Δn(gases) = 0, pressure/volume changes have no effect on equilibrium position.
- Addition of an inert (non‑reactive) gas:
- At constant volume: no effect on equilibrium position (partial pressures of reactants/products unchanged).
- At constant pressure: adding inert gas increases volume → can shift equilibrium (similar to volume increase).
- Catalysts:
- Catalysts increase rates of both forward and backward reactions equally; they speed attainment of equilibrium but do not change K or the equilibrium composition.
Practical tip: to predict direction, consider which side of the equation will reduce the imposed change.
Reaction quotient Q and direction prediction
- Compute Q the same way as K but using current (instantaneous) pressures/concentrations.
- Compare Q to K to predict spontaneous shift:
- Q < K → forward
- Q = K → at equilibrium
- Q > K → backward
Graphical illustrations (qualitative)
- Concentration vs time: reactant concentration falls, product concentration rises, both become constant at equilibrium.
- Rate vs time: forward and reverse rates approach each other and become equal at equilibrium.
Worked‑problem methodology / ICE approach
General ICE (Initial — Change — Equilibrium) steps:
- I (initial): write initial concentrations or pressures.
- C (change): express changes using stoichiometric multiples (e.g., −2x, +3x).
- E (equilibrium): write equilibrium expressions (e.g., [A] = A0 − 2x).
- Substitute equilibrium expressions into the K expression and solve for x.
Common formats and notes:
- Initial concentrations given + K given → use ICE with concentrations and Kc.
- Initial pressures given + Kp given → same ICE method using partial pressures (or convert from mole fractions & Ptotal).
- Initial moles given + Ptotal/Kp given → convert moles → mole fractions xi = ni / n_total, then Pi = xi · Ptotal and use Kp.
- If volume not provided, it’s common to assume V = 1 L to convert moles → molarity for Kc problems.
- If solids/pure liquids are present, omit their activity (set = 1) in the K expression.
- Use Dalton’s law when needed: Pi = (ni / n_total) · P_total.
Conversions and care:
- Stoichiometric coefficients are the exponents in K expressions.
- When reversing/multiplying/adding reactions, adjust K appropriately (reciprocal, power, product).
- For Kp, be consistent with units of pressure (atm commonly used). Useful conversions: 1 atm = 760 mmHg = 1.013×10^5 Pa; 1 bar = 10^5 Pa.
Thermodynamics and K
- ΔG° = −RT ln K relates standard free-energy change and K.
- If ΔG° = 0 → K = 1.
- Use van ’t Hoff equation for how K changes with temperature:
- ln(K2/K1) = −ΔH°/R (1/T2 − 1/T1) (use for numerical estimates when ΔH° is approximately constant).
Practical exam tips
- Memorize concise NCERT definitions/lines for exam answers.
- In numericals:
- Remember common unit conversions (atm, mmHg, Pa).
- If initial moles are given without volume, assume 1 L unless instructed otherwise.
- Identify the unknown x and set up equations with correct stoichiometric factors; omit pure solids/liquids from K.
- For multi‑step reaction combinations: overall K = product of individual Ks.
- Practice using calculators during study (note exam rules may differ).
Common example systems (for intuition)
- N2 + 3H2 ⇌ 2NH3 (illustrates Δn and Kp/Kc relation)
- PCl5 ⇌ PCl3 + Cl2 (illustrates gaseous equilibria and pressure/volume effects)
- Solid ⇌ liquid at the melting point (rate of melting = rate of crystallization)
- Liquid ⇌ vapor at the boiling point (vaporization rate = condensation rate)
- Dissolution/crystallization (saturation: rate of dissolution = rate of crystallization; solubility varies with temperature and, for gases, with pressure)
Problems and practice focus areas
- Writing correct K expressions (products raised to stoichiometric powers over reactants); omit solids/pure liquids.
- Predicting direction using Q vs K.
- ICE table practice for:
- Initial concentrations
- Initial pressures
- Initial mole numbers & total pressure
- K given in different forms (Kc, Kp, etc.)
- Algebraic manipulation of K for reversed/multiplied/combined reactions.
- Numerical use of van ’t Hoff relation to relate K at different temperatures.
- Units of K: derive from Δn (difference in gaseous moles).
Key formulas (concise)
- Kc = [C]^c [D]^d / ([A]^a [B]^b)
- Kp = (PC)^c (PD)^d / (PA)^a (PB)^b)
- Kp = Kc (RT)^{Δn}, Δn = (gas moles products) − (gas moles reactants)
- ΔG° = −RT ln K
- van ’t Hoff: ln(K2/K1) = −ΔH°/R (1/T2 − 1/T1)
- Q defined the same as K but using instantaneous concentrations/pressures
Speakers / sources referenced
- Main lecturer/instructor: Prachand (NEET / classroom teacher — video presenter).
- NCERT (text referenced for definitions and standard statements).
- Law of Mass Action: Guldberg & Waage.
- Le Chatelier: Le Chatelier’s principle.
- Dalton: Dalton’s law of partial pressures.
- Henry: Henry’s law for gas solubility in liquids.
- Thermodynamics relations: standard textbook thermodynamics.
- (Various cultural analogies used by the lecturer — e.g., Dhoni, movie references — not scientific sources.)
Optional supplementary materials you might prepare
- One‑page ICE table template and a worked example (step‑by‑step) for each common problem type (initial concentrations, initial pressures, initial moles).
- A short set of representative NCERT/NEET practice problems with full solutions.
Category
Educational
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