Summary of "Problem on Stress, strain and elastic constants"

Summary of the Video: Problem on Stress, Strain and Elastic Constants

Main Ideas and Concepts

The video discusses a mechanics problem related to stress, strain, and elastic constants in a metal bar. It involves calculating various mechanical properties and deformation parameters when a compressive load is applied. Key points include:

Problem Description

Goal: Calculate the following mechanical properties:

Methodology / Step-by-Step Instructions

  1. Identify Given Data:

    • Cross-sectional dimension (side length) = 50 mm
    • Original length (L₀) = 200 mm
    • Compressive load (F) = 500 N
    • Contraction in length (ΔL) = 0.5 mm
    • Increase in thickness (Δd) = 0.04 mm
  2. Calculate Cross-Sectional Area (A): [ A = \text{side}^2 = 50 \text{ mm} \times 50 \text{ mm} = 2500 \text{ mm}^2 ]

  3. Calculate Longitudinal Stress (σ): [ \sigma = \frac{F}{A} ] (Convert units as necessary to N/m² or Pascals)

  4. Calculate Longitudinal Strain (ε): [ \epsilon = \frac{\Delta L}{L_0} = \frac{0.5}{200} = 0.0025 ]

  5. Calculate Young’s Modulus (E): [ E = \frac{\sigma}{\epsilon} ]

  6. Calculate Lateral Strain (ε_lateral): [ \epsilon_{\text{lateral}} = \frac{\Delta d}{d} = \frac{0.04}{50} = 0.0008 ]

  7. Calculate Poisson’s Ratio (ν): [ \nu = - \frac{\epsilon_{\text{lateral}}}{\epsilon} ]

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