Summary of "Top 5 Dynamic Programming Patterns for Coding Interviews - For Beginners"
Main ideas and concepts (5 dynamic programming patterns)
Setup / purpose
- The speaker introduces a Google spreadsheet containing:
- Five DP categories/patterns
- Sample problems for each category
- Links to prior “video solutions” for many of the samples
- The goal is to understand fundamental DP patterns to solve harder DP problems later.
- Mentions overlap between categories: some problems can fit multiple patterns.
1) Fibonacci Numbers (1D DP, bottom-up)
Definition / recurrence
- Let the Fibonacci function be f(n).
- Base cases:
- f(0) = 0
- f(1) = 1
- Recurrence for n ≥ 2:
- f(n) = f(n−1) + f(n−2)
Why it’s a DP problem
- A naive recursion forms a decision tree where subproblems repeat (e.g., computing f(4) appears multiple times inside the tree for f(6)).
- Dynamic programming avoids recomputation by reusing previously computed results.
Bottom-up approach
- Compute from smaller base cases up to the target.
- Example behavior:
- Compute f(2) using f(0) and f(1)
- Compute f(3) using the last two computed values
- Continue until reaching f(6)
Space optimization
- Although it’s conceptually a 1D array of size n, you only need the last two values:
- Keep f(n−1) and f(n−2)
- Older values can be discarded since future results depend only on the two most recent ones.
Typical problems mentioned
- Climbing Stairs is cited as falling into the Fibonacci pattern.
2) 0/1 Knapsack (2D DP)
Problem framing (subset-sum style)
- Given a set of items/coins and a target sum (example target: 5).
- Key question emphasized:
- Is it possible to reach the target sum? (boolean DP)
Why it’s “0/1”
- Each coin can be used either:
- 0 times, or
- 1 time
- Not an infinite number of times.
Brute force inefficiency
- For n coins, each coin has 2 choices (use or not use), giving 2ⁿ combinations.
Subproblem structure
- Split the decision based on whether to use a particular coin:
- If you use the current coin, the target decreases (e.g., from 5 to 4)
- If you skip it, the target stays the same but you move to the next coins
DP grid dimensions
- One dimension: target value (from 0 up to the original target)
- Another dimension: coin index / allowed set
- e.g., “we can use coins from some position to the end” (or equivalently, first k coins)
Base cases
- If target = 0, return true (sum of zero is always achievable: using nothing).
- If the target becomes negative, it is treated as invalid/false (as described in the explanation).
Transition idea (boolean feasibility)
- For a DP cell representing:
- “Can we achieve target T using the allowed set of coins?”
- Check:
- Use coin i → move to reduced target with remaining allowed coins
- Skip coin i → keep target, reduce the allowed coin set accordingly
3) Unbounded Knapsack (2D DP)
Problem framing (coin change style)
- Determine feasibility (and relates to coin change).
- Difference from 0/1:
- Each coin can be used infinitely many times.
Relationship to 0/1 knapsack
- The same kind of 2D DP grid applies.
- What changes is the dependency direction / transition:
- In unbounded knapsack, choosing a coin does not remove it from availability.
Transition direction intuition
- When computing a cell, the dependencies imply:
- Use coin again → move in a way that allows staying with the same coin conceptually (e.g., staying in the same “row” while reducing the target)
- Skip coin → move to the next coin option (conceptually move “down”)
Bottom-up filling order
- Dependencies are arranged so the speaker describes computing:
- from the bottom, and from already-computed neighbors (bottom and right)
- This matches the typical bottom-up tabulation idea used in other 2D DP problems.
Typical problem mentioned
- Coin Change is explicitly referenced.
4) Longest Common Subsequence (LCS) (2D DP)
Subsequence concept
- A subsequence:
- preserves relative order
- does not need to be contiguous
- For each character, you decide whether to include it or not.
- Order matters (subsequence formation is explained conceptually).
LCS definition
- Given two strings (example: ABC and ACE):
- Find the longest subsequence common to both.
Recursive/decision logic
- Compare characters starting from the beginning:
- If characters match:
- take the match and reduce to the remaining suffixes of both strings
- If characters do not match:
- branch into two subproblems:
- skip from the first string
- or skip from the second string
- branch into two subproblems:
- If characters match:
DP grid dimensions
- One dimension: positions in string 1
- Other dimension: positions in string 2
- Grid size is proportional to the product of string lengths.
Base cases
- If both suffixes are empty (reached ends of both strings), LCS length is 0.
- The speaker emphasizes that correct DP bases correspond to empty-string comparisons.
Transition / movement in grid
- For a matched cell:
- move diagonally (advance both strings)
- For a non-matched cell:
- consider moves corresponding to:
- skip from string 1 (e.g., move down)
- skip from string 2 (e.g., move right)
- consider moves corresponding to:
- Bottom-up recommendation:
- compute from the bottom-right toward the top-left so dependencies are ready.
5) Palindrome DP pattern (expand-around-center + memoization)
Goal
- Use DP to avoid repeated work in palindrome-related problems (e.g., counting palindromes).
Why naive checking is expensive
- Checking whether a substring is a palindrome by comparing ends takes O(n) per substring.
- Repeating this across many substrings causes major inefficiency.
DP “trick”: expand outward using known palindrome status
- Instead of repeatedly rebuilding and re-checking from scratch:
- Start with palindromes of minimal length
- Then expand outward by adding one character to the left and one to the right
- Key observation:
- If the inner substring is already known to be a palindrome and the new outer characters match, then the expanded substring is also a palindrome.
- This makes palindrome verification for expanded substrings O(1) after the inner result is known.
Odd-length palindromes
- Start with substrings of length 1 (always palindromes).
- Then expand outward by adding two characters total each time:
- producing odd-length palindromes.
Even-length palindromes
- Start with substrings of length 2.
- If the two characters match, expand outward similarly.
Impact
- This “expand outward with DP” technique underlies many palindrome DP problems efficiently.
- Mentions multiple problems in the spreadsheet that require this method.
Overall lessons / meta-points
- DP patterns rely on:
- identifying overlapping subproblems
- choosing an appropriate DP state representation
- often using bottom-up tabulation (and sometimes space optimization)
- Categories can overlap (a single problem may match multiple patterns).
- The spreadsheet serves as a curated learning path with linked prior solutions.
Speakers / sources
- Speaker: YouTube video narrator/instructor (no name provided in the subtitles)
- Source referenced: The instructor’s Google spreadsheet (linked in the description per subtitles) and the instructor’s previous YouTube videos (e.g., climbing stairs, coin change, LCS)
- Website/platform referenced: LeetCode
Category
Educational
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