SSC CGL 2026 LIVE MOCK SOLUTION | Ft. Abhishek Ojha Sir | #ssc #ssccgl2026 #ssccgl

Main Ideas / Concepts

• The speaker conducts an SSC CGL 2026 live mock test, solving multiple MCQ-style questions.
• The focus is on speed + strategy:
  • Solving live to demonstrate an approach.
  • Promising a later, detailed breakdown to help achieve about ~10 minutes per similar mock, based on a prior performance (e.g., 25 questions in 10 minutes).

• The mock covers common SSC topics with quick techniques, including:

  • Algebraic expressions and identities
  • Profit/loss percentage chaining
  • Factors, multiples, and divisibility checks
  • Ratio/comparison (including ratios derived from sequential percentage changes)
  • Successive discounts
  • Geometry (equilateral triangles, similarity, chords/hemispheres/cylinders, isosceles triangles)
  • Simple interest and percentages
  • Trigonometric identity-style equivalences
  • Distance–time meeting problems
  • Pipes/cylinders/hemispheres (volume-based computations, “volume conservation” type logic)
  • Work–rate problems (combined work, LCM of time)
  • Number theory (prime counting over ranges with endpoint constraints)

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Methodology / Step-by-Step Strategy (Implicit Approach)

• Start the mock live and choose the fastest route per question (sometimes using partial checks like “multiple answer” logic vs full derivations).
• For “fixed/habit-type” SSC questions, use a template method rather than deriving from scratch.
• For percentage changes:
  • Convert percent changes into multiplicative factors (e.g., 26% profit → ×1.26).
  • Prefer working with differences in percent rather than recalculating everything.
• For work–rate/time problems:
  • Use LCM and ratios instead of complex equations.
• For geometry/volumes:
  • Use standard formulas and simplify by substitution.
  • For hollow cylinders, compute outer and inner radii, then take the volume difference.

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Detailed Instruction Examples Used in the Mock

Profit/Loss via Sequential Profit Percentages

• Given:
  • First selling at 26% profit
  • Selling price increases by 2250, leading to 41% profit
• Method used:
  • Observe that profit rises from 26% to 41% → +15% change in profit amount.
  • Treat the “additional 2250” as the monetary value of that 15%.
  • Back-calculate the original cost/marked-related value using the percent-to-amount mapping.
  • Then compute the price for another profit scenario (example mentioned: 12% profit) using percent-to-total-factor logic (described as ~112%/total-factor style).

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Successive Discounts

• Given:
  • Successive discounts of 5%, 10%, 20%
  • Original price = 1500
• Method used:
  • Convert each discount into a multiplicative factor:
    • After 5%: × (19/20)
    • After 10%: × (9/10)
    • After 20%: × (4/5) (standard step implied)
  • Multiply factors, simplify quickly using cancellation/quick factoring.
  • Choose the option matching the final value.

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Work–Rate Problem (LCM + Remaining Work)

• Given:
  • Lalit completes in 15 days → rate = 1/15
  • Laxman completes in 25 days → rate = 1/25
  • They work together for 5 days
  • Remaining work is completed by Lalit + Devan in 4 days
• Method shown:
  • Compute LCM(15, 25) to combine efficiencies quickly.
    • LCM stated as 75
  • Compute progress after 5 days using an LCM-based capacity/proportional capacity arithmetic style.
  • Determine remaining work units.
  • Use Lalit + Devan in 4 days to compute Devan’s efficiency:
    • (Remaining work / 4) gives combined capacity
    • Subtract Lalit’s capacity to isolate Devan’s capacity
  • Find time for Devan alone from total work vs Devan’s capacity.

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Replacement / “Mixture” Style Problem (Fraction Retention)

• Given:
  • Container = 64 liters
  • Remove 8 liters and replace with water
  • Operation is performed 3 times
• Method described:
  • Each replacement leaves a retained fraction:
    • Remaining after one operation = 1 − (8/64) = 7/8
  • Repeating 3 times multiplies retention:
    • After 3 times = (7/8)³
  • (Intermediate arithmetic attempts were mentioned in the transcript.)

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Distance–Time Meeting Problem (Two Trains)

• Given:
  • Train A: leaves at 6:00, speed 60
  • Train B: leaves at 8:00, speed 90, moving toward A
  • Distance between them at B’s departure = 540
• Method shown:
  • Distance A covers from 6:00 to 8:00:
    • 60 × 2 = 120
  • Remaining distance at 8:00:
    • 540 − 120 = 420
  • Use relative time division by speeds to compute time to meet.
  • Convert time to minutes:
    • Meeting time comes out approx. 2 hours 48 minutes
  • Final meeting time:
    • 8:00 + 2:48 = 10:48

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Hemisphere → Cylinder (Volume Conservation)

• Given:
  • Hemisphere radius = 6 cm
  • Hemisphere is melted into a cylinder (height implied/garbled in text)
  • Find cylinder radius
• Method:
  • Hemisphere volume: (\frac{2}{3}\pi r^3)
  • Cylinder volume: (\pi R^2 h)
  • Set volumes equal, substitute r = 6, solve for R², then R.

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Isosceles Triangle Angle/Median Relation

• Given:
  • Triangle ABC with AB = AC
  • Angle at A = 55°
  • AD is the median to BC
• Method used:
  • In an isosceles triangle, the median to the base has special angle-bisector/perpendicular-bisector properties.
  • The transcript concludes a relevant angle/segment relation results in 90 (exact variable naming is garbled in the summary).

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Number Theory: Prime Counting in a Range

• Question theme:
  • Count primes in a range like “between 146 and 96” (ordering suggests the real range is 96 to 146).
• Method (high-level):
  • Use known/remembered prime counts across smaller intervals (e.g., 1–50, 51–100, etc.).
  • Adjust by excluding primes outside the required range (example mentions excluding primes at 97 and 99).
  • Apply corrections to reach the final prime count.

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Speakers / Sources Featured

• Abhishek Ojha (Sir) — host/instructor conducting the SSC CGL mock and explaining strategy.
• Mentions like “Sir” / “kids / brother” refer to audience addressing and not additional speakers.