Video summary

Visualizing vectors in 2 dimensions | Two-dimensional motion | Physics | Khan Academy

Main summary

Key takeaways

Educational

Main ideas and lessons

  • Moving beyond one dimension: Earlier problems often treated motion as 1D (forward/back, right/left, or up/down). This video extends the idea to 2D (and notes the generalization to 3+ dimensions).

  • What a vector is: A vector has:

    • Magnitude (the arrow’s length)
    • Direction (the direction the arrow points)
  • How to add vectors visually in 2D:

    • Vectors can be shifted (moved) without changing them, as long as they keep the same magnitude and direction.
    • To compute A + B:
      1. Draw A
      2. Shift B so its tail starts at the head of A
      3. The vector from the tail of A to the head of the shifted B is C = A + B
    • Interpretation example (displacement): If you displace by A and then by B, the net displacement is the vector sum.
  • Decomposing a 2D vector into components:

    • Any 2D vector X can be written as the sum of its components:
      • X = X_horizontal + X_vertical
    • This turns a 2D problem into two separate 1D problems:
      • one along the horizontal axis
      • one along the vertical axis
  • Using trigonometry to find component magnitudes (math method):

    • Define vector A with magnitude 5, making an angle 36.8699° with the positive x-axis.
    • Components:
      • A_y (vertical component; “opposite” the angle)
      • A_x (horizontal component; “adjacent” to the angle)
    • The components form a right triangle:
      • hypotenuse = |A| = 5
      • opposite side = |A_y|
      • adjacent side = |A_x|

Detailed instruction-style bullet points (methodology)

1) Vector addition in 2D (graphical method)

  • Draw vector A with the correct length and direction.
  • Draw vector B with the correct length and direction.
  • Shift vector B so that:
    • the tail of B is placed at the head of A
  • The resulting sum C = A + B is:
    • the vector that starts at the tail of A and ends at the head of the shifted B

2) Decompose a vector into horizontal/vertical components (conceptual)

  • For a vector X in 2D:
    • construct a horizontal component and a vertical component that add tip-to-tail to X
  • Represent it as:
    • X = (horizontal component) + (vertical component)
  • Use this to split a 2D problem into:
    • a horizontal 1D problem
    • a vertical 1D problem

3) Compute component magnitudes using trig (given magnitude and angle)

Given:

  • Vector A magnitude = 5
  • Angle θ = 36.8699° measured from the positive x-axis

Triangle relationships:

  • sin(θ) = opposite / hypotenuse
  • cos(θ) = adjacent / hypotenuse

Compute components:

  • Vertical component magnitude:
    • |A_y| = |A| · sin(θ) = 5 · sin(36.8699°) ≈ 3
  • Horizontal component magnitude:
    • |A_x| = |A| · cos(θ) = 5 · cos(36.8699°) ≈ 4

Result:

  • A_y ≈ 3
  • A_x ≈ 4
  • This matches a 3-4-5 right triangle

4) Why components matter (preview of next idea)

  • If a vector represents velocity (example preview):
    • A velocity of magnitude 5 m/s in the given direction can be split into:
      • upward component: 3 m/s
      • rightward component: 4 m/s
  • This converts a 2D motion problem into two independent 1D component problems

Speakers / sources featured

  • Khan Academy (Voiceover)

Original video